Jul 19, 2016 · Is x>y? (1) x√> y x> y --> if x = 4 x = 4 and y = 1 y = 1 then the answer will be YES but if x = 14 x = 1 4 and y = 13 y = 1 3 then the answer will be NO. Two different answers, hence not …

2 days ago · Since x and y are integers, (x − y)2 (x y) 2 and y2 y 2 are both perfect squares. Since the left side must sum to 27, y2 y 2 must be equal to a perfect square less than 27, yielding the following …

Mar 22, 2022 · Is |x-y|>|x|-|y|? Probably the best way to solve this problem is plug-in method. Though there are two properties worth to remember: 1. Always true: |x + y| ≤ |x| + |y| | x + y | ≤ | x | + | y |, …

Mar 20, 2026 · x|y| = −1 x y = 1 means the NUMERIC value of x and y has to be same , sign may not be.. The second point is that since |y| will be positive, x will be NEGATIVE..

5 days ago · But in B. y+z x y + z x we can not be sure that we'll be able factor out x x from z z thus this option might not be an integer (for example x=y=4 and z=2). Answer: B. Alternately you could juts …

Jan 4, 2021 · If x + y/xy = 1, then y = (A) x/x - 1 (B) x/x + 1 (C) x - 1/x (D) x + 1/x (E) x­­ I had a very strange way of solving this. Might not always work. I plugged in numbers and already wasted enough …

Mar 19, 2026 · Right hand side, |x + y| | x + y |, is an absolute value, which is always non-negative. So LHS must also be more than or equal to zero: |x| −|y| ≥ 0 | x | | y | ≥ 0, or |x| ≥ |y| | x | ≥ | y |.

2 days ago · x2 x 2 is always positive in this case. y − x y x will be always negative, as the value of x x is greater than the value of y y. Hence, x2y − x3 x 2 y x 3 will always be negative.

Mar 19, 2026 · |x − y| | x y | represents the distance between x x & y y on the number line. S1 will only be true when x x and y y are only opposite sides of 0. Now, we need to check this statement for …

Mar 20, 2026 · x, y and z are positive integers so their minimum value is 1 each. None of the three can be 1 because then the sum of reciprocals will become 1 with just that number.